Council Of Scientific and Industrial Research CSIR Online Are Invited Online Application Form for the NET / JRF Examination 2018. Those Candidates Are Interested in the Following Vacancy and Completed the All Eligibility Criteria Can Read the Full Notification and Apply Online.
|Last Date for Complete Form||22/03/2019.|
|Date of Admit Card.||June 2019|
| Date of Examination||16/09/2019.|
|Date of Result.||Notified Soon|
|SC / ST / PH||Rs.250/-.|
|Mode of Payment||Application Fee Can be Submitted through E-Challan Making Payment at Any Branch of Indian Bank.|
CSIR UGC NET / JRF June 2019 Examination Online Form Subject
CSIR awards Junior Research Fellowship (JRF) to a large number of candidates each year. Educational background of candidates includes BS-4 years program, BE, B.Tech, B.Pharma, MBBS, Integrated BS-MS, MSc or equivalent, B.Sc Hons.
|1. Chemical Science.|
|2. Earth, Atmospheric, Ocean and Planetary Sciences.|
|3. Life Sciences.|
|4. Mathematical Sciences.|
|5. Physical Sciences.|
Educational Qualification for CSIR UGC NET / JRF June 2019 Examination Online Form
UGC NET / JRF June 2019 Examination
For More Details Please Check the Detailed Brochure.
|Educational Qualifications||Candidate Must Have Passed M.Sc or Equivalent Degree / BE / B.Tech / B.Pharma / MBBS with at least 55% Marks (50% for SC / ST and PH Candidates) or Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible for CSIR NET 2018.|
Age Limit Details of CSIR UGC NET / JRF June 2019 Examination Online Form
As on 01/01/2019
Age Relaxation As Per Govt Rules.
|Maximum Age for JRF||28 Years.|
|Maximum Age for NET||No Age Limit.|
Selection Process of CSIR UGC NET / JRF June 2019 Examination Online Form
Selection May be Based on.
CSIR UGC NET / JRF June 2019 Examination Online Form Syllabus
Joint CSIR-UGC NET examination syllabus is formed keeping in mind the purpose of this exam. Syllabus of CSIR NET is divided into three parts namely Part A, Part B, Part C.
- Part A – This is common to all subjects. Questions will be on General Aptitude with emphasis on logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparison, series formation, puzzles.
- Part B – These will be subject-related conventional multiple choice questions.
- Part C – Here there will be higher value questions to test knowledge of scientific concepts and/or application of scientific concepts. To answer such analytical questions, scientific knowledge has to be applied.
CSIR UGC NET / JRF June 2019 Exam Pattern
Joint CSIR-UGC NET will be a single paper with multiple choice questions. Candidate will appear in any one subject. It is a 3 hours duration exam of 200 marks.
- Chemical sciences
- Earth, Atmospheric, Ocean and Planetary Sciences
- Life sciences
- Mathematical Sciences
- Physical sciences
|Duration of exam||3 hours|
|Mode of exam||Pen and paper based|
|Languages in which question paper will be available||Hindi, English|
|Morning session timings||9 am to 12 noon|
|Afternoon session timings||from 2 pm to 5 pm|
How to Apply about CSIR UGC NET / JRF June 2019 Examination Online Form
| 1. The Candidates can Apply through Online mode.|
|2. Click Apply Online Link is given on Our Website in Important link Section.|
|3. Candidates are required to Register before Applying for the Post and Already
Register Candidate Not needs to register Again.|
|4.After Successful Registration system will Generate a Login ID and Password on your Screen.|
|5. Login with the ID and Password then Start Filling Your Application form and Read all the instruction before Applying for the Post.|
|6. Upload the Scanned Copy of Documents in Prescribed Size and format.|
|7. Take Printout of your Application form for future Reference.|
|8. Online Application can be Submitted on or Before 22nd March 2019.|
Important Links to Apply for CSIR UGC NET / JRF June 2019 Examination Online Form